#1197 · Energy & Environment Tool

Geothermal Heat Pump Annual Output Calculator

Estimate the annual useful heating output of a geothermal heat pump system from rated capacity, equivalent full-load hours, seasonal coefficient of performance, and availability. The calculator separates delivered heat from estimated electricity input and source heat, helping you check an energy model or compare system operating assumptions.

Calculator

Annual energy inputs
kW
h/yr
COP
%

How to use this calculator

  1. Enter the system and operating values using consistent units.
  2. Review any efficiency, availability, coverage, or reserve assumptions.
  3. Select Calculate to update the result and supporting metrics.
  4. Test alternative values to understand sensitivity before making a decision.

Formula

Annual heat output (kWh) = capacity (kW) × full-load hours × availability
Electricity input = heat output ÷ seasonal COP
Source heat = heat output − electricity input

What the result means

Annual useful output is the heat delivered to the building, not the electrical energy consumed. Equivalent full-load hours already summarize the seasonal load profile, so do not also multiply by a separate load factor.

Actual output depends on weather, controls, distribution losses, defrost operation, ground or source temperatures, and equipment performance.

Example calculation

A 12 kW system operating for 2,200 equivalent full-load hours at 98% availability delivers 25,872 kWh of useful heat per year.

Tips for better results

  • Use seasonal rather than catalog efficiency.
  • Derive full-load hours from a load model when possible.
  • Keep heating and cooling seasons separate.
  • Account for backup heat outside this estimate.
  • Compare the result with utility data after commissioning.

Frequently asked questions

Is geothermal heat pump annual output the same as electricity use?

No. Useful heat output equals electricity input multiplied by seasonal COP.

What are equivalent full-load hours?

They convert varying part-load operation into the hours the unit would run at rated capacity.

Why include system availability?

It reduces theoretical output for maintenance, outages, and other unavailable time.

Can I use cooling output in this calculator?

Use it only if capacity, full-load hours, and efficiency all describe the same cooling season.

Should I enter rated COP or seasonal COP?

Use a seasonal value that reflects temperatures and part-load operation for a more realistic annual estimate.

Energy-flow variables

MeasureUnitDefinition
CapacitykW thermalRated useful heat rate
OutputkWh thermal/yearUseful heat delivered
ElectricitykWh electric/yearOutput divided by COP
Source heatkWh thermal/yearOutput less electricity

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