Build an annual aquarium ownership budget from recurring food, water treatment, electricity, maintenance, and veterinary or livestock reserve costs. Add one-time equipment spending and spread it over a chosen planning life so the annual figure reflects both operations and equipment replacement. All rates remain user-entered because local utility and care costs vary.
The result is an annualized budget for the entered plan. Equipment is allocated evenly across its planning life, even though the cash purchase may occur all at once.
Actual electricity use changes as heaters and chillers cycle. Measure equipment with an energy meter when a more accurate budget is needed, and keep emergency funds separate from predictable annual costs.
With $35 monthly care, 120 W running 24 hours/day at $0.18/kWh, a $300 reserve, and $900 of equipment spread over 5 years: electricity is $189.22, recurring care is $420, equipment is $180, and the annual total is $1,089.22.
No. Use it to check arithmetic and planning assumptions, then follow the applicable veterinarian, product label, welfare standard, or qualified care guidance.
A zero is accepted only where it represents no cost, no feed, no water change, or another valid absence. Values used as divisors or required physical dimensions must be greater than zero.
Actual results depend on conditions not fully represented by a compact model, including animal needs, measured consumption, losses, operating practices, and local prices.
Keep the unrounded value for planning. For medication or treatment measurements, use only the rounding and measuring method approved on the label or by the responsible professional.
Update them whenever weight, occupancy, tank volume, husbandry routine, prices, equipment use, or the underlying care plan changes.
| Input type | How to choose it |
|---|---|
| Physical measurement | Use an observed or measured value in the displayed unit. |
| Rate or percentage | Use the applicable care plan, product label, or operating record. |
| Planning period | Keep the period consistent with the formula and result. |